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33z-11z^2=0
a = -11; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·(-11)·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*-11}=\frac{-66}{-22} =+3 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*-11}=\frac{0}{-22} =0 $
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